1311144204631 has 2 divisors, whose sum is σ = 1311144204632. Its totient is φ = 1311144204630.

The previous prime is 1311144204613. The next prime is 1311144204677. The reversal of 1311144204631 is 1364024411131.

Together with previous prime (1311144204613) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1311144204631 - 2⁵ = 1311144204599 is a prime.

It is a super-2 number, since 2×1311144204631² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311144204593 and 1311144204602.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311144204031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655572102315 + 655572102316.

It is an arithmetic number, because the mean of its divisors is an integer number (655572102316).

Almost surely, 2^{1311144204631} is an apocalyptic number.

1311144204631 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311144204631 is an equidigital number, since it uses as much as digits as its factorization.

1311144204631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 1311144204631 its reverse (1364024411131), we get a palindrome (2675168615762).

The spelling of 1311144204631 in words is "one trillion, three hundred eleven billion, one hundred forty-four million, two hundred four thousand, six hundred thirty-one".