Base | Representation |
---|---|
bin | 11101110100000100001111… |
… | …101101010000100001110010 |
3 | 122012021002001020121110021001 |
4 | 131310010033231100201302 |
5 | 114141242430421231002 |
6 | 1142512145231152214 |
7 | 36422126355256006 |
oct | 3564041755204162 |
9 | 565232036543231 |
10 | 131121320102002 |
11 | 3886326a96542a |
12 | 1285823497566a |
13 | 58218c2390a19 |
14 | 245443cdc2706 |
15 | 1025b76b26a87 |
hex | 77410fb50872 |
131121320102002 has 4 divisors (see below), whose sum is σ = 196681980153006. Its totient is φ = 65560660051000.
The previous prime is 131121320101969. The next prime is 131121320102033. The reversal of 131121320102002 is 200201023121131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 130872936480841 + 248383621161 = 11439971^2 + 498381^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32780330025499 + ... + 32780330025502.
Almost surely, 2131121320102002 is an apocalyptic number.
131121320102002 is a deficient number, since it is larger than the sum of its proper divisors (65560660051004).
131121320102002 is an equidigital number, since it uses as much as digits as its factorization.
131121320102002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65560660051003.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131121320102002 its reverse (200201023121131), we get a palindrome (331322343223133).
The spelling of 131121320102002 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred twenty million, one hundred two thousand, two".
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