Base | Representation |
---|---|
bin | 10011000101001111100… |
… | …110100101101110001001 |
3 | 11122100200210022102122121 |
4 | 103011033212211232021 |
5 | 132441020414310241 |
6 | 2442223025251241 |
7 | 163511151460111 |
oct | 23051746455611 |
9 | 4570623272577 |
10 | 1311300541321 |
11 | 466134a74141 |
12 | 19217ba93b21 |
13 | 9686937c094 |
14 | 47678330041 |
15 | 2419b07dad1 |
hex | 1314f9a5b89 |
1311300541321 has 2 divisors, whose sum is σ = 1311300541322. Its totient is φ = 1311300541320.
The previous prime is 1311300541261. The next prime is 1311300541403. The reversal of 1311300541321 is 1231450031131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1260149934096 + 51150607225 = 1122564^2 + 226165^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311300541321 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311300541921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650270660 + 655650270661.
It is an arithmetic number, because the mean of its divisors is an integer number (655650270661).
Almost surely, 21311300541321 is an apocalyptic number.
It is an amenable number.
1311300541321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311300541321 is an equidigital number, since it uses as much as digits as its factorization.
1311300541321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 1311300541321 its reverse (1231450031131), we get a palindrome (2542750572452).
The spelling of 1311300541321 in words is "one trillion, three hundred eleven billion, three hundred million, five hundred forty-one thousand, three hundred twenty-one".
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