1311300541413 has 10 divisors (see below), whose sum is σ = 1958856364454. Its totient is φ = 874200360888.

The previous prime is 1311300541403. The next prime is 1311300541423. The reversal of 1311300541413 is 3141450031131.

1311300541413 is a `hidden beast` number, since 1 + 3 + 113 + 0 + 0 + 541 + 4 + 1 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (1311300541403) and next prime (1311300541423).

It can be written as a sum of positive squares in only one way, i.e., 843666131169 + 467634410244 = 918513^2 + 683838^2 .

It is not a de Polignac number, because 1311300541413 - 2¹² = 1311300537317 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311300541403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 8094447706 + ... + 8094447867.

Almost surely, 2^{1311300541413} is an apocalyptic number.

It is an amenable number.

1311300541413 is a deficient number, since it is larger than the sum of its proper divisors (647555823041).

1311300541413 is an equidigital number, since it uses as much as digits as its factorization.

1311300541413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16188895585 (or 16188895576 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

Adding to 1311300541413 its reverse (3141450031131), we get a palindrome (4452750572544).

The spelling of 1311300541413 in words is "one trillion, three hundred eleven billion, three hundred million, five hundred forty-one thousand, four hundred thirteen".