Base | Representation |
---|---|
bin | 11101110100010110101010… |
… | …101011100101010010010001 |
3 | 122012022222002201222101212122 |
4 | 131310112222223211102101 |
5 | 114142103433100003101 |
6 | 1142525220055104025 |
7 | 36423426465524201 |
oct | 3564265253452221 |
9 | 565288081871778 |
10 | 131141100000401 |
11 | 388706a01218a7 |
12 | 12860035072015 |
13 | 582372529390a |
14 | 2455397d72401 |
15 | 10264333b751b |
hex | 7745aaae5491 |
131141100000401 has 16 divisors (see below), whose sum is σ = 131567720739840. Its totient is φ = 130715115345360.
The previous prime is 131141100000353. The next prime is 131141100000403. The reversal of 131141100000401 is 104000001141131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131141100000401 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131141100000401.
It is not an unprimeable number, because it can be changed into a prime (131141100000403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2724646106 + ... + 2724694236.
It is an arithmetic number, because the mean of its divisors is an integer number (8222982546240).
Almost surely, 2131141100000401 is an apocalyptic number.
It is an amenable number.
131141100000401 is a deficient number, since it is larger than the sum of its proper divisors (426620739439).
131141100000401 is a wasteful number, since it uses less digits than its factorization.
131141100000401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54556.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 131141100000401 its reverse (104000001141131), we get a palindrome (235141101141532).
The spelling of 131141100000401 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, four hundred one", and thus it is an aban number.
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