131141324000020 has 48 divisors (see below), whose sum is σ = 275545156879440. Its totient is φ = 52428270698496.

The previous prime is 131141323999883. The next prime is 131141324000041. The reversal of 131141324000020 is 20000423141131.

It can be written as a sum of positive squares in 8 ways, for example, as 47037677993604 + 84103646006416 = 6858402^2 + 9170804^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131141323999955 and 131141324000000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 702817296 + ... + 703003864.

It is an arithmetic number, because the mean of its divisors is an integer number (5740524101655).

Almost surely, 2^{131141324000020} is an apocalyptic number.

131141324000020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141324000020 is an abundant number, since it is smaller than the sum of its proper divisors (144403832879420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141324000020 is a wasteful number, since it uses less digits than its factorization.

131141324000020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205324 (or 205322 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 131141324000020 its reverse (20000423141131), we get a palindrome (151141747141151).

The spelling of 131141324000020 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, twenty", and thus it is an aban number.