Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000111010010011110011010 |
3 | 122012022222201121121121000021 |
4 | 131310112321013102132122 |
5 | 114142104432042110120 |
6 | 1142525300105101054 |
7 | 36423435465646333 |
oct | 3564267107223632 |
9 | 565288647547007 |
10 | 131141342144410 |
11 | 3887080487a214 |
12 | 128600a218778a |
13 | 58237634b55b0 |
14 | 24553bc1a528a |
15 | 1026449798aaa |
hex | 7745b91d279a |
131141342144410 has 64 divisors (see below), whose sum is σ = 269410157194752. Its totient is φ = 45531781641216.
The previous prime is 131141342144399. The next prime is 131141342144447. The reversal of 131141342144410 is 14441243141131.
It is a Harshad number since it is a multiple of its sum of digits (34).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24461724 + ... + 29336983.
It is an arithmetic number, because the mean of its divisors is an integer number (4209533706168).
Almost surely, 2131141342144410 is an apocalyptic number.
131141342144410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131141342144410 is an abundant number, since it is smaller than the sum of its proper divisors (138268815050342).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141342144410 is a wasteful number, since it uses less digits than its factorization.
131141342144410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53799847.
The product of its (nonzero) digits is 18432, while the sum is 34.
Adding to 131141342144410 its reverse (14441243141131), we get a palindrome (145582585285541).
The spelling of 131141342144410 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-two million, one hundred forty-four thousand, four hundred ten".
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