Base | Representation |
---|---|
bin | 11101110100011000100011… |
… | …111011111010001100100001 |
3 | 122012100011100111220201112012 |
4 | 131310120203323322030201 |
5 | 114142122114341322424 |
6 | 1142530154005442305 |
7 | 36423531060141251 |
oct | 3564304373721441 |
9 | 565304314821465 |
10 | 131143134323489 |
11 | 38871544481952 |
12 | 12860502410395 |
13 | 582398a8978a2 |
14 | 245550c203961 |
15 | 1026501ca9b0e |
hex | 774623efa321 |
131143134323489 has 2 divisors, whose sum is σ = 131143134323490. Its totient is φ = 131143134323488.
The previous prime is 131143134323471. The next prime is 131143134323581. The reversal of 131143134323489 is 984323431341131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78109536961600 + 53033597361889 = 8837960^2 + 7282417^2 .
It is a cyclic number.
It is not a de Polignac number, because 131143134323489 - 220 = 131143133274913 is a prime.
It is not a weakly prime, because it can be changed into another prime (131143134323449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571567161744 + 65571567161745.
It is an arithmetic number, because the mean of its divisors is an integer number (65571567161745).
Almost surely, 2131143134323489 is an apocalyptic number.
It is an amenable number.
131143134323489 is a deficient number, since it is larger than the sum of its proper divisors (1).
131143134323489 is an equidigital number, since it uses as much as digits as its factorization.
131143134323489 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2239488, while the sum is 50.
The spelling of 131143134323489 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirty-four million, three hundred twenty-three thousand, four hundred eighty-nine".
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