13114334310041 has 4 divisors (see below), whose sum is σ = 13151485399092. Its totient is φ = 13077183220992.

The previous prime is 13114334310023. The next prime is 13114334310079. The reversal of 13114334310041 is 14001343341131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8778065328400 + 4336268981641 = 2962780^2 + 2082371^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114334310041 - 2⁶ = 13114334309977 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13114334309986 and 13114334310013.

It is not an unprimeable number, because it can be changed into a prime (13114334310241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18575543996 + ... + 18575544701.

It is an arithmetic number, because the mean of its divisors is an integer number (3287871349773).

Almost surely, 2^{13114334310041} is an apocalyptic number.

It is an amenable number.

13114334310041 is a deficient number, since it is larger than the sum of its proper divisors (37151089051).

13114334310041 is an equidigital number, since it uses as much as digits as its factorization.

13114334310041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37151089050.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13114334310041 its reverse (14001343341131), we get a palindrome (27115677651172).

The spelling of 13114334310041 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred ten thousand, forty-one".