Base | Representation |
---|---|
bin | 10011000101011101010… |
… | …110001111111100011001 |
3 | 11122101021212012222222111 |
4 | 103011131112033330121 |
5 | 132442003432420331 |
6 | 2442301543552321 |
7 | 163516651512100 |
oct | 23053526177431 |
9 | 4571255188874 |
10 | 1311531138841 |
11 | 466243155500 |
12 | 19222515b6a1 |
13 | 968a508a311 |
14 | 4769abd9037 |
15 | 241b142ddb1 |
hex | 1315d58ff19 |
1311531138841 has 81 divisors (see below), whose sum is σ = 1705048600437. Its totient is φ = 1005137567280.
The previous prime is 1311531138817. The next prime is 1311531138913. The reversal of 1311531138841 is 1488311351131.
The square root of 1311531138841 is 1145221.
It is a perfect power (a square), and thus also a powerful number.
It is not a de Polignac number, because 1311531138841 - 27 = 1311531138713 is a prime.
It is a super-2 number, since 2×13115311388412 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311531138794 and 1311531138803.
It is not an unprimeable number, because it can be changed into a prime (1311531136841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 80 ways as a sum of consecutive naturals, for example, 9435475750 + ... + 9435475888.
Almost surely, 21311531138841 is an apocalyptic number.
1311531138841 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1311531138841 is the 1145221-st square number.
1311531138841 is the 572611-st centered octagonal number.
It is an amenable number.
1311531138841 is a deficient number, since it is larger than the sum of its proper divisors (393517461596).
1311531138841 is an equidigital number, since it uses as much as digits as its factorization.
1311531138841 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 528 (or 264 counting only the distinct ones).
The product of its digits is 34560, while the sum is 40.
Adding to 1311531138841 its reverse (1488311351131), we get a palindrome (2799842489972).
The spelling of 1311531138841 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, one hundred thirty-eight thousand, eight hundred forty-one".
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