131200136541445 has 4 divisors (see below), whose sum is σ = 157440163849740. Its totient is φ = 104960109233152.

The previous prime is 131200136541437. The next prime is 131200136541517. The reversal of 131200136541445 is 544145631002131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74809663950564 + 56390472590881 = 8649258^2 + 7509359^2 .

It is a cyclic number.

It is not a de Polignac number, because 131200136541445 - 2³ = 131200136541437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131200136541398 and 131200136541407.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13120013654140 + ... + 13120013654149.

It is an arithmetic number, because the mean of its divisors is an integer number (39360040962435).

Almost surely, 2^{131200136541445} is an apocalyptic number.

It is an amenable number.

131200136541445 is a deficient number, since it is larger than the sum of its proper divisors (26240027308295).

131200136541445 is an equidigital number, since it uses as much as digits as its factorization.

131200136541445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26240027308294.

The product of its (nonzero) digits is 172800, while the sum is 40.

Adding to 131200136541445 its reverse (544145631002131), we get a palindrome (675345767543576).

The spelling of 131200136541445 in words is "one hundred thirty-one trillion, two hundred billion, one hundred thirty-six million, five hundred forty-one thousand, four hundred forty-five".