Base | Representation |
---|---|
bin | 11101110101001111011011… |
… | …110100110110000110110000 |
3 | 122012112210102201210011120012 |
4 | 131311033123310312012300 |
5 | 114144103301314214240 |
6 | 1143013220324034052 |
7 | 36431015131451204 |
oct | 3565173364660660 |
9 | 565483381704505 |
10 | 131202054054320 |
11 | 3889452a0a0777 |
12 | 1286ba06532928 |
13 | 58293ba591b42 |
14 | 24582db412b04 |
15 | 1027cee772b65 |
hex | 7753dbd361b0 |
131202054054320 has 20 divisors (see below), whose sum is σ = 305044775676480. Its totient is φ = 52480821621696.
The previous prime is 131202054054271. The next prime is 131202054054341. The reversal of 131202054054320 is 23450450202131.
It is a tau number, because it is divible by the number of its divisors (20).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 820012837760 + ... + 820012837919.
It is an arithmetic number, because the mean of its divisors is an integer number (15252238783824).
Almost surely, 2131202054054320 is an apocalyptic number.
131202054054320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131202054054320 is an abundant number, since it is smaller than the sum of its proper divisors (173842721622160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131202054054320 is a wasteful number, since it uses less digits than its factorization.
131202054054320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1640025675692 (or 1640025675686 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 32.
The spelling of 131202054054320 in words is "one hundred thirty-one trillion, two hundred two billion, fifty-four million, fifty-four thousand, three hundred twenty".
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