13121117 has 2 divisors, whose sum is σ = 13121118. Its totient is φ = 13121116.

The previous prime is 13121099. The next prime is 13121159. The reversal of 13121117 is 71112131.

13121117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a m-pointer prime, because the next prime (13121159) can be obtained adding 13121117 to its product of digits (42).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13039321 + 81796 = 3611^2 + 286^2 .

It is an emirp because it is prime and its reverse (71112131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13121117 is a prime.

It is a super-2 number, since 2×13121117² = 344327422655378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13121095 and 13121104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560558 + 6560559.

It is an arithmetic number, because the mean of its divisors is an integer number (6560559).

Almost surely, 2^13121117 is an apocalyptic number.

It is an amenable number.

13121117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121117 is an equidigital number, since it uses as much as digits as its factorization.

13121117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 42, while the sum is 17.

The square root of 13121117 is about 3622.3082419916. The cubic root of 13121117 is about 235.8614347459.

Adding to 13121117 its reverse (71112131), we get a palindrome (84233248).

The spelling of 13121117 in words is "thirteen million, one hundred twenty-one thousand, one hundred seventeen".