131213004421241 has 4 divisors (see below), whose sum is σ = 131213046566400. Its totient is φ = 131212962276084.

The previous prime is 131213004421229. The next prime is 131213004421253. The reversal of 131213004421241 is 142124400312131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (131213004421229) and next prime (131213004421253).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131213004421241 is a prime.

It is a super-2 number, since 2×131213004421241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131213004421211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15994661 + ... + 22765218.

It is an arithmetic number, because the mean of its divisors is an integer number (32803261641600).

Almost surely, 2^{131213004421241} is an apocalyptic number.

It is an amenable number.

131213004421241 is a deficient number, since it is larger than the sum of its proper divisors (42145159).

131213004421241 is an equidigital number, since it uses as much as digits as its factorization.

131213004421241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42145158.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131213004421241 its reverse (142124400312131), we get a palindrome (273337404733372).

The spelling of 131213004421241 in words is "one hundred thirty-one trillion, two hundred thirteen billion, four million, four hundred twenty-one thousand, two hundred forty-one".