1312141034131 has 2 divisors, whose sum is σ = 1312141034132. Its totient is φ = 1312141034130.

The previous prime is 1312141034129. The next prime is 1312141034161. The reversal of 1312141034131 is 1314301412131.

It is a weak prime.

It is an emirp because it is prime and its reverse (1314301412131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312141034131 - 2¹ = 1312141034129 is a prime.

It is a super-2 number, since 2×1312141034131² (a number of 25 digits) contains 22 as substring.

Together with 1312141034129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1312141034096 and 1312141034105.

It is not a weakly prime, because it can be changed into another prime (1312141034161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656070517065 + 656070517066.

It is an arithmetic number, because the mean of its divisors is an integer number (656070517066).

Almost surely, 2^{1312141034131} is an apocalyptic number.

1312141034131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312141034131 is an equidigital number, since it uses as much as digits as its factorization.

1312141034131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1312141034131 its reverse (1314301412131), we get a palindrome (2626442446262).

The spelling of 1312141034131 in words is "one trillion, three hundred twelve billion, one hundred forty-one million, thirty-four thousand, one hundred thirty-one".