Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010111101000111011111 |
3 | 1201110111020120010102020221 |
4 | 2332331030302331013133 |
5 | 3204444200324441411 |
6 | 43524204211022211 |
7 | 2523030432330346 |
oct | 276751462750737 |
9 | 51414216112227 |
10 | 13122413515231 |
11 | 41aa2033685a9 |
12 | 157b26589a967 |
13 | 742590bb0cb7 |
14 | 3351b1b08b5d |
15 | 17b526483071 |
hex | bef4ccbd1df |
13122413515231 has 2 divisors, whose sum is σ = 13122413515232. Its totient is φ = 13122413515230.
The previous prime is 13122413515151. The next prime is 13122413515339. The reversal of 13122413515231 is 13251531422131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13122413515231 - 29 = 13122413514719 is a prime.
It is a super-2 number, since 2×131224135152312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122413915231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206757615 + 6561206757616.
It is an arithmetic number, because the mean of its divisors is an integer number (6561206757616).
Almost surely, 213122413515231 is an apocalyptic number.
13122413515231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122413515231 is an equidigital number, since it uses as much as digits as its factorization.
13122413515231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21600, while the sum is 34.
Adding to 13122413515231 its reverse (13251531422131), we get a palindrome (26373944937362).
The spelling of 13122413515231 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fifteen thousand, two hundred thirty-one".
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