Base | Representation |
---|---|
bin | 11101110101101010011001… |
… | …001001101111100010000100 |
3 | 122012122120011001010020202200 |
4 | 131311222121021233202010 |
5 | 114200042042024330040 |
6 | 1143034404513034500 |
7 | 36433061344053045 |
oct | 3565523111574204 |
9 | 565576131106680 |
10 | 131231000230020 |
11 | 388a5833498a29 |
12 | 12875544555a30 |
13 | 582c051522a62 |
14 | 24598858dc8cc |
15 | 1028945ad7630 |
hex | 775a9926f884 |
131231000230020 has 144 divisors (see below), whose sum is σ = 399034874784000. Its totient is φ = 34909886995200.
The previous prime is 131231000230019. The next prime is 131231000230067. The reversal of 131231000230020 is 20032000132131.
131231000230020 is a `hidden beast` number, since 1 + 31 + 2 + 310 + 0 + 0 + 2 + 300 + 20 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 131231000229975 and 131231000230002.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1848314481 + ... + 1848385479.
Almost surely, 2131231000230020 is an apocalyptic number.
131231000230020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131231000230020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199517437392000).
131231000230020 is an abundant number, since it is smaller than the sum of its proper divisors (267803874553980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131231000230020 is a wasteful number, since it uses less digits than its factorization.
131231000230020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95826 (or 95821 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 131231000230020 its reverse (20032000132131), we get a palindrome (151263000362151).
The spelling of 131231000230020 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, two hundred thirty thousand, twenty".
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