Base | Representation |
---|---|
bin | 111101000110111111… |
… | …0100100110010111111 |
3 | 110112201201022000212011 |
4 | 1322031332210302333 |
5 | 4122230114304413 |
6 | 140141531552051 |
7 | 12324012115513 |
oct | 1721576446277 |
9 | 415651260764 |
10 | 131231009983 |
11 | 50722536157 |
12 | 21524bbb627 |
13 | c4b4c358c8 |
14 | 64ccb8c143 |
15 | 3630e7733d |
hex | 1e8dfa4cbf |
131231009983 has 2 divisors, whose sum is σ = 131231009984. Its totient is φ = 131231009982.
The previous prime is 131231009971. The next prime is 131231009999. The reversal of 131231009983 is 389900132131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131231009983 - 25 = 131231009951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131231009933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615504991 + 65615504992.
It is an arithmetic number, because the mean of its divisors is an integer number (65615504992).
Almost surely, 2131231009983 is an apocalyptic number.
131231009983 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231009983 is an equidigital number, since it uses as much as digits as its factorization.
131231009983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 40.
The spelling of 131231009983 in words is "one hundred thirty-one billion, two hundred thirty-one million, nine thousand, nine hundred eighty-three".
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