Base | Representation |
---|---|
bin | 111101000111010010… |
… | …1111100111011010001 |
3 | 110112202102201110121010 |
4 | 1322032211330323101 |
5 | 4122240240114213 |
6 | 140142541121133 |
7 | 12324165630231 |
oct | 1721645747321 |
9 | 415672643533 |
10 | 131241332433 |
11 | 50728346602 |
12 | 215285591a9 |
13 | c4b710b173 |
14 | 64d02b7cc1 |
15 | 3631d15ac3 |
hex | 1e8e97ced1 |
131241332433 has 16 divisors (see below), whose sum is σ = 179618092992. Its totient is φ = 85207800000.
The previous prime is 131241332413. The next prime is 131241332449. The reversal of 131241332433 is 334233142131.
It is not a de Polignac number, because 131241332433 - 213 = 131241324241 is a prime.
It is a super-4 number, since 4×1312413324334 (a number of 46 digits) contains 4444 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 131241332433.
It is not an unprimeable number, because it can be changed into a prime (131241332413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3531843 + ... + 3568808.
It is an arithmetic number, because the mean of its divisors is an integer number (11226130812).
Almost surely, 2131241332433 is an apocalyptic number.
It is an amenable number.
131241332433 is a deficient number, since it is larger than the sum of its proper divisors (48376760559).
131241332433 is a wasteful number, since it uses less digits than its factorization.
131241332433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7100816.
The product of its digits is 15552, while the sum is 30.
Adding to 131241332433 its reverse (334233142131), we get a palindrome (465474474564).
The spelling of 131241332433 in words is "one hundred thirty-one billion, two hundred forty-one million, three hundred thirty-two thousand, four hundred thirty-three".
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