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1313151143917 is a prime number
BaseRepresentation
bin10011000110111101111…
…010000100111111101101
311122112110202112210011111
4103012331322010333231
5133003313143101132
62443130414152021
7163605052362004
oct23067572047755
94575422483144
101313151143917
114669a4650278
121925b77b2611
1396aa28a88c2
14477b2019c3b
1524258780647
hex131bde84fed

1313151143917 has 2 divisors, whose sum is σ = 1313151143918. Its totient is φ = 1313151143916.

The previous prime is 1313151143903. The next prime is 1313151143947. The reversal of 1313151143917 is 7193411513131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1177201130121 + 135950013796 = 1084989^2 + 368714^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313151143917 - 27 = 1313151143789 is a prime.

It is a super-2 number, since 2×13131511439172 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1313151143917.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313151143947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656575571958 + 656575571959.

It is an arithmetic number, because the mean of its divisors is an integer number (656575571959).

Almost surely, 21313151143917 is an apocalyptic number.

It is an amenable number.

1313151143917 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313151143917 is an equidigital number, since it uses as much as digits as its factorization.

1313151143917 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34020, while the sum is 40.

The spelling of 1313151143917 in words is "one trillion, three hundred thirteen billion, one hundred fifty-one million, one hundred forty-three thousand, nine hundred seventeen".