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131330305537 = 467281221211
BaseRepresentation
bin111101001001111100…
…1010110111000000001
3110112222122010202202021
41322103321112320001
54122431024234122
6140155440121441
712326326115104
oct1722371267001
9415878122667
10131330305537
11507735963a2
1221552306281
13c4cc690882
1464dc03873b
153639a3d1c7
hex1e93e56e01

131330305537 has 4 divisors (see below), whose sum is σ = 131611527216. Its totient is φ = 131049083860.

The previous prime is 131330305501. The next prime is 131330305567. The reversal of 131330305537 is 735503033131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131330305537 - 219 = 131329781249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131330305567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140610139 + ... + 140611072.

It is an arithmetic number, because the mean of its divisors is an integer number (32902881804).

Almost surely, 2131330305537 is an apocalyptic number.

It is an amenable number.

131330305537 is a deficient number, since it is larger than the sum of its proper divisors (281221679).

131330305537 is an equidigital number, since it uses as much as digits as its factorization.

131330305537 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 281221678.

The product of its (nonzero) digits is 42525, while the sum is 34.

Adding to 131330305537 its reverse (735503033131), we get a palindrome (866833338668).

The spelling of 131330305537 in words is "one hundred thirty-one billion, three hundred thirty million, three hundred five thousand, five hundred thirty-seven".

Divisors: 1 467 281221211 131330305537