1313410081 has 3 divisors (see below), whose sum is σ = 1313446323. Its totient is φ = 1313373840.

The previous prime is 1313410073. The next prime is 1313410097. The reversal of 1313410081 is 1800143131.

The square root of 1313410081 is 36241.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in only one way, i.e., 8755681 + 1304654400 = 2959^2 + 36120^2 .

It is not a de Polignac number, because 1313410081 - 2³ = 1313410073 is a prime.

It is a super-2 number, since 2×1313410081² = 3450092081744853122, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313410001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 18121 + ... + 54361.

It is an arithmetic number, because the mean of its divisors is an integer number (437815441).

Almost surely, 2^1313410081 is an apocalyptic number.

1313410081 is the 36241-st square number.

1313410081 is the 18121-st centered octagonal number.

It is an amenable number.

1313410081 is a deficient number, since it is larger than the sum of its proper divisors (36242).

1313410081 is an frugal number, since it uses more digits than its factorization.

1313410081 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72482 (or 36241 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 22.

The cubic root of 1313410081 is about 1095.1327879109.

The spelling of 1313410081 in words is "one billion, three hundred thirteen million, four hundred ten thousand, eighty-one".