1314241011403 has 4 divisors (see below), whose sum is σ = 1321502011648. Its totient is φ = 1306980011160.

The previous prime is 1314241011401. The next prime is 1314241011409. The reversal of 1314241011403 is 3041101424131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314241011403 - 2¹ = 1314241011401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314241011401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3630499851 + ... + 3630500212.

It is an arithmetic number, because the mean of its divisors is an integer number (330375502912).

Almost surely, 2^{1314241011403} is an apocalyptic number.

1314241011403 is a deficient number, since it is larger than the sum of its proper divisors (7261000245).

1314241011403 is an equidigital number, since it uses as much as digits as its factorization.

1314241011403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7261000244.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1314241011403 its reverse (3041101424131), we get a palindrome (4355342435534).

The spelling of 1314241011403 in words is "one trillion, three hundred fourteen billion, two hundred forty-one million, eleven thousand, four hundred three".