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13143113 = 25152363
BaseRepresentation
bin110010001000…
…110001001001
3220201201221222
4302020301021
511331034423
61145411425
7216500054
oct62106111
926651858
1013143113
117467685
124499b75
1329523b9
141a61a9b
1512493c8
hexc88c49

13143113 has 4 divisors (see below), whose sum is σ = 13195728. Its totient is φ = 13090500.

The previous prime is 13143089. The next prime is 13143149. The reversal of 13143113 is 31134131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13143113 - 212 = 13139017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13143091 and 13143100.

It is not an unprimeable number, because it can be changed into a prime (13143173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25931 + ... + 26432.

It is an arithmetic number, because the mean of its divisors is an integer number (3298932).

Almost surely, 213143113 is an apocalyptic number.

It is an amenable number.

13143113 is a deficient number, since it is larger than the sum of its proper divisors (52615).

13143113 is an equidigital number, since it uses as much as digits as its factorization.

13143113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52614.

The product of its digits is 108, while the sum is 17.

The square root of 13143113 is about 3625.3431561716. The cubic root of 13143113 is about 235.9931590950.

Adding to 13143113 its reverse (31134131), we get a palindrome (44277244).

The spelling of 13143113 in words is "thirteen million, one hundred forty-three thousand, one hundred thirteen".

Divisors: 1 251 52363 13143113