Base | Representation |
---|---|
bin | 1011111101000011000011… |
… | …1000010101100000110001 |
3 | 1201112111110112112102110122 |
4 | 2333100300320111200301 |
5 | 3210320211010002210 |
6 | 43542000452540025 |
7 | 2524403125445150 |
oct | 277206070254061 |
9 | 51474415472418 |
10 | 13143420000305 |
11 | 4208102a3a771 |
12 | 1583348921615 |
13 | 74455ac5681a |
14 | 336205949597 |
15 | 17bd55761b55 |
hex | bf430e15831 |
13143420000305 has 64 divisors (see below), whose sum is σ = 18383087697408. Its totient is φ = 8835445893120.
The previous prime is 13143420000253. The next prime is 13143420000311. The reversal of 13143420000305 is 50300002434131.
It is not a de Polignac number, because 13143420000305 - 212 = 13143419996209 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1281904559 + ... + 1281914811.
It is an arithmetic number, because the mean of its divisors is an integer number (287235745272).
Almost surely, 213143420000305 is an apocalyptic number.
It is an amenable number.
13143420000305 is a deficient number, since it is larger than the sum of its proper divisors (5239667697103).
13143420000305 is a wasteful number, since it uses less digits than its factorization.
13143420000305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13706.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 13143420000305 its reverse (50300002434131), we get a palindrome (63443422434436).
The spelling of 13143420000305 in words is "thirteen trillion, one hundred forty-three billion, four hundred twenty million, three hundred five", and thus it is an aban number.
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