Base | Representation |
---|---|
bin | 10011001000011000110… |
… | …000001111100000101001 |
3 | 11122200101222111112112221 |
4 | 103020120300033200221 |
5 | 133014423333322301 |
6 | 2443541542034041 |
7 | 163660610414005 |
oct | 23103060174051 |
9 | 4580358445487 |
10 | 1314675292201 |
11 | 467606a24457 |
12 | 192962118921 |
13 | 96c865a44ab |
14 | 478b8607705 |
15 | 242e7499da1 |
hex | 13218c0f829 |
1314675292201 has 2 divisors, whose sum is σ = 1314675292202. Its totient is φ = 1314675292200.
The previous prime is 1314675292193. The next prime is 1314675292211. The reversal of 1314675292201 is 1022925764131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1099931098176 + 214744194025 = 1048776^2 + 463405^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314675292201 - 23 = 1314675292193 is a prime.
It is a super-2 number, since 2×13146752922012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314675292211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657337646100 + 657337646101.
It is an arithmetic number, because the mean of its divisors is an integer number (657337646101).
Almost surely, 21314675292201 is an apocalyptic number.
It is an amenable number.
1314675292201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314675292201 is an equidigital number, since it uses as much as digits as its factorization.
1314675292201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 43.
The spelling of 1314675292201 in words is "one trillion, three hundred fourteen billion, six hundred seventy-five million, two hundred ninety-two thousand, two hundred one".
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