Base | Representation |
---|---|
bin | 11000100101101101… |
… | …10100111110110101 |
3 | 1021002000111201112122 |
4 | 30102312310332311 |
5 | 204014010431230 |
6 | 10021540525325 |
7 | 645065616536 |
oct | 142266647665 |
9 | 37060451478 |
10 | 13201264565 |
11 | 5664851505 |
12 | 26850b0845 |
13 | 1324cac768 |
14 | 8d339a68d |
15 | 523e5abe5 |
hex | 312db4fb5 |
13201264565 has 16 divisors (see below), whose sum is σ = 15883978608. Its totient is φ = 10532745216.
The previous prime is 13201264547. The next prime is 13201264603. The reversal of 13201264565 is 56546210231.
It can be written as a sum of positive squares in 8 ways, for example, as 997422724 + 12203841841 = 31582^2 + 110471^2 .
It is a cyclic number.
It is not a de Polignac number, because 13201264565 - 222 = 13197070261 is a prime.
It is a super-2 number, since 2×132012645652 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4206677 + ... + 4209813.
It is an arithmetic number, because the mean of its divisors is an integer number (992748663).
Almost surely, 213201264565 is an apocalyptic number.
It is an amenable number.
13201264565 is a deficient number, since it is larger than the sum of its proper divisors (2682714043).
13201264565 is a wasteful number, since it uses less digits than its factorization.
13201264565 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5128.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13201264565 its reverse (56546210231), we get a palindrome (69747474796).
The spelling of 13201264565 in words is "thirteen billion, two hundred one million, two hundred sixty-four thousand, five hundred sixty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •