Base | Representation |
---|---|
bin | 11110000001100111011010… |
… | …110111100001111000101011 |
3 | 122022120002102200210122000211 |
4 | 132001213122313201320223 |
5 | 114302021400011132243 |
6 | 1144504015410241551 |
7 | 36546321413513563 |
oct | 3601473267417053 |
9 | 568502380718024 |
10 | 132052441505323 |
11 | 390921426a2159 |
12 | 129887935862b7 |
13 | 588b651647981 |
14 | 248752d723da3 |
15 | 103eec143ed9d |
hex | 7819dade1e2b |
132052441505323 has 2 divisors, whose sum is σ = 132052441505324. Its totient is φ = 132052441505322.
The previous prime is 132052441505191. The next prime is 132052441505399. The reversal of 132052441505323 is 323505144250231.
It is a strong prime.
It is an emirp because it is prime and its reverse (323505144250231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132052441505323 - 225 = 132052407950891 is a prime.
It is not a weakly prime, because it can be changed into another prime (132052441605323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026220752661 + 66026220752662.
It is an arithmetic number, because the mean of its divisors is an integer number (66026220752662).
Almost surely, 2132052441505323 is an apocalyptic number.
132052441505323 is a deficient number, since it is larger than the sum of its proper divisors (1).
132052441505323 is an equidigital number, since it uses as much as digits as its factorization.
132052441505323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 132052441505323 its reverse (323505144250231), we get a palindrome (455557585755554).
The spelling of 132052441505323 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, five hundred five thousand, three hundred twenty-three".
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