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132052441505323 is a prime number
BaseRepresentation
bin11110000001100111011010…
…110111100001111000101011
3122022120002102200210122000211
4132001213122313201320223
5114302021400011132243
61144504015410241551
736546321413513563
oct3601473267417053
9568502380718024
10132052441505323
11390921426a2159
12129887935862b7
13588b651647981
14248752d723da3
15103eec143ed9d
hex7819dade1e2b

132052441505323 has 2 divisors, whose sum is σ = 132052441505324. Its totient is φ = 132052441505322.

The previous prime is 132052441505191. The next prime is 132052441505399. The reversal of 132052441505323 is 323505144250231.

It is a strong prime.

It is an emirp because it is prime and its reverse (323505144250231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132052441505323 - 225 = 132052407950891 is a prime.

It is not a weakly prime, because it can be changed into another prime (132052441605323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026220752661 + 66026220752662.

It is an arithmetic number, because the mean of its divisors is an integer number (66026220752662).

Almost surely, 2132052441505323 is an apocalyptic number.

132052441505323 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052441505323 is an equidigital number, since it uses as much as digits as its factorization.

132052441505323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 132052441505323 its reverse (323505144250231), we get a palindrome (455557585755554).

The spelling of 132052441505323 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, five hundred five thousand, three hundred twenty-three".