Base | Representation |
---|---|
bin | 11000100110111000… |
… | …10110011101001011 |
3 | 1021002201000110121011 |
4 | 30103130112131023 |
5 | 204024020213003 |
6 | 10022531424351 |
7 | 645245335312 |
oct | 142334263513 |
9 | 37081013534 |
10 | 13211101003 |
11 | 566a35a7a1 |
12 | 26884550b7 |
13 | 1327044a39 |
14 | 8d47db279 |
15 | 524c5046d |
hex | 31371674b |
13211101003 has 4 divisors (see below), whose sum is σ = 13666656240. Its totient is φ = 12755545768.
The previous prime is 13211100997. The next prime is 13211101027. The reversal of 13211101003 is 30010111231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13211101003 is a prime.
It is a super-2 number, since 2×132111010032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13211101063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227777575 + ... + 227777632.
It is an arithmetic number, because the mean of its divisors is an integer number (3416664060).
Almost surely, 213211101003 is an apocalyptic number.
13211101003 is a deficient number, since it is larger than the sum of its proper divisors (455555237).
13211101003 is an equidigital number, since it uses as much as digits as its factorization.
13211101003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 455555236.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13211101003 its reverse (30010111231), we get a palindrome (43221212234).
The spelling of 13211101003 in words is "thirteen billion, two hundred eleven million, one hundred one thousand, three".
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