132114230200035 has 24 divisors (see below), whose sum is σ = 229072276905264. Its totient is φ = 70438068037440.

The previous prime is 132114230200031. The next prime is 132114230200103. The reversal of 132114230200035 is 530002032411231.

132114230200035 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 1 + 423 + 0 + 200 + 0 + 35 = 666.

It is not a de Polignac number, because 132114230200035 - 2² = 132114230200031 is a prime.

It is a super-2 number, since 2×132114230200035² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132114230199981 and 132114230200008.

It is not an unprimeable number, because it can be changed into a prime (132114230200031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 476000056 + ... + 476277525.

It is an arithmetic number, because the mean of its divisors is an integer number (9544678204386).

Almost surely, 2^{132114230200035} is an apocalyptic number.

132114230200035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132114230200035 is a deficient number, since it is larger than the sum of its proper divisors (96958046705229).

132114230200035 is a wasteful number, since it uses less digits than its factorization.

132114230200035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 952280675 (or 952280672 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 132114230200035 its reverse (530002032411231), we get a palindrome (662116262611266).

The spelling of 132114230200035 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred thirty million, two hundred thousand, thirty-five".