Base | Representation |
---|---|
bin | 11110000011000011010101… |
… | …001010110110011010011011 |
3 | 122022220112011110220110100010 |
4 | 132003003111022312122123 |
5 | 114310131003304422101 |
6 | 1145021220250413003 |
7 | 36556414125265356 |
oct | 3603032512663233 |
9 | 568815143813303 |
10 | 132151130154651 |
11 | 3911aa85888073 |
12 | 129a3936131163 |
13 | 5897a4b576b6a |
14 | 248c21254b29d |
15 | 104284a4962d6 |
hex | 7830d52b669b |
132151130154651 has 4 divisors (see below), whose sum is σ = 176201506872872. Its totient is φ = 88100753436432.
The previous prime is 132151130154643. The next prime is 132151130154671. The reversal of 132151130154651 is 156451031151231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 132151130154651 - 23 = 132151130154643 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132151130154671) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22025188359106 + ... + 22025188359111.
It is an arithmetic number, because the mean of its divisors is an integer number (44050376718218).
Almost surely, 2132151130154651 is an apocalyptic number.
132151130154651 is a deficient number, since it is larger than the sum of its proper divisors (44050376718221).
132151130154651 is an equidigital number, since it uses as much as digits as its factorization.
132151130154651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44050376718220.
The product of its (nonzero) digits is 54000, while the sum is 39.
The spelling of 132151130154651 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred thirty million, one hundred fifty-four thousand, six hundred fifty-one".
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