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132315433 is a prime number
BaseRepresentation
bin1111110001011…
…11100100101001
3100012222022122121
413320233210221
5232333043213
621043551241
73164443165
oct770574451
9305868577
10132315433
11687635a8
123838b521
1321549673
1413803ca5
15b93988d
hex7e2f929

132315433 has 2 divisors, whose sum is σ = 132315434. Its totient is φ = 132315432.

The previous prime is 132315383. The next prime is 132315439. The reversal of 132315433 is 334513231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118200384 + 14115049 = 10872^2 + 3757^2 .

It is a cyclic number.

It is not a de Polignac number, because 132315433 - 29 = 132314921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132315398 and 132315407.

It is not a weakly prime, because it can be changed into another prime (132315439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157716 + 66157717.

It is an arithmetic number, because the mean of its divisors is an integer number (66157717).

Almost surely, 2132315433 is an apocalyptic number.

It is an amenable number.

132315433 is a deficient number, since it is larger than the sum of its proper divisors (1).

132315433 is an equidigital number, since it uses as much as digits as its factorization.

132315433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3240, while the sum is 25.

The square root of 132315433 is about 11502.8445612379. The cubic root of 132315433 is about 509.5695881591.

Adding to 132315433 its reverse (334513231), we get a palindrome (466828664).

The spelling of 132315433 in words is "one hundred thirty-two million, three hundred fifteen thousand, four hundred thirty-three".