Base | Representation |
---|---|
bin | 11110000110101111110010… |
… | …010111101111010011001001 |
3 | 122100210210111201100121200020 |
4 | 132012233302113233103021 |
5 | 114323310441411034423 |
6 | 1145334010010331053 |
7 | 36613642622134620 |
oct | 3606576227572311 |
9 | 570723451317606 |
10 | 132405023143113 |
11 | 39208722855156 |
12 | 12a24b92429a89 |
13 | 58b598102a406 |
14 | 249a619db86b7 |
15 | 1049259e484e3 |
hex | 786bf25ef4c9 |
132405023143113 has 16 divisors (see below), whose sum is σ = 202563860115456. Its totient is φ = 75358578906000.
The previous prime is 132405023143093. The next prime is 132405023143139. The reversal of 132405023143113 is 311341320504231.
It is not a de Polignac number, because 132405023143113 - 213 = 132405023134921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132405023148113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12559757881 + ... + 12559768422.
It is an arithmetic number, because the mean of its divisors is an integer number (12660241257216).
Almost surely, 2132405023143113 is an apocalyptic number.
It is an amenable number.
132405023143113 is a deficient number, since it is larger than the sum of its proper divisors (70158836972343).
132405023143113 is a wasteful number, since it uses less digits than its factorization.
132405023143113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25119526564.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 132405023143113 its reverse (311341320504231), we get a palindrome (443746343647344).
The spelling of 132405023143113 in words is "one hundred thirty-two trillion, four hundred five billion, twenty-three million, one hundred forty-three thousand, one hundred thirteen".
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