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BaseRepresentation
bin101000011010001010101
32111021100101
411003101111
5314332432
644214101
714153254
oct5032125
92437311
101324117
11824913
1253a331
13374902
1426679b
151b24e7
hex143455

1324117 has 2 divisors, whose sum is σ = 1324118. Its totient is φ = 1324116.

The previous prime is 1324097. The next prime is 1324123. The reversal of 1324117 is 7114231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1052676 + 271441 = 1026^2 + 521^2 .

It is an emirp because it is prime and its reverse (7114231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1324117 - 215 = 1291349 is a prime.

It is a plaindrome in base 14.

It is a junction number, because it is equal to n+sod(n) for n = 1324094 and 1324103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1324187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662058 + 662059.

It is an arithmetic number, because the mean of its divisors is an integer number (662059).

21324117 is an apocalyptic number.

It is an amenable number.

1324117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324117 is an equidigital number, since it uses as much as digits as its factorization.

1324117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 168, while the sum is 19.

The square root of 1324117 is about 1150.7028287095. The cubic root of 1324117 is about 109.8100578818.

Adding to 1324117 its reverse (7114231), we get a palindrome (8438348).

It can be divided in two parts, 1324 and 117, that added together give a palindrome (1441).

The spelling of 1324117 in words is "one million, three hundred twenty-four thousand, one hundred seventeen".