Base | Representation |
---|---|
bin | 1100000010101111010101… |
… | …1010011011110110111110 |
3 | 1201212211212110012001021021 |
4 | 3000223311122123312332 |
5 | 3213420442334212141 |
6 | 44054532030054354 |
7 | 2534434304442442 |
oct | 300536532336676 |
9 | 51784773161237 |
10 | 13241206554046 |
11 | 42456229a1939 |
12 | 159a29934a3ba |
13 | 750843007543 |
14 | 33ac40a2c822 |
15 | 17e67a4c56d1 |
hex | c0af569bdbe |
13241206554046 has 8 divisors (see below), whose sum is σ = 19864786294944. Its totient is φ = 6619611122400.
The previous prime is 13241206554019. The next prime is 13241206554049. The reversal of 13241206554046 is 64045560214231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13241206553993 and 13241206554011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13241206554049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 496060630 + ... + 496087321.
It is an arithmetic number, because the mean of its divisors is an integer number (2483098286868).
Almost surely, 213241206554046 is an apocalyptic number.
13241206554046 is a deficient number, since it is larger than the sum of its proper divisors (6623579740898).
13241206554046 is an equidigital number, since it uses as much as digits as its factorization.
13241206554046 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 992154626.
The product of its (nonzero) digits is 691200, while the sum is 43.
Adding to 13241206554046 its reverse (64045560214231), we get a palindrome (77286766768277).
The spelling of 13241206554046 in words is "thirteen trillion, two hundred forty-one billion, two hundred six million, five hundred fifty-four thousand, forty-six".
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