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1324254753139 is a prime number
BaseRepresentation
bin10011010001010011101…
…110111111000101110011
311200121010120221120112111
4103101103232333011303
5133144033204100024
62452204303110151
7164450160451363
oct23212356770563
94617116846474
101324254753139
1147068231521a
121947962a2357
1397b5210b786
144814697a9a3
15246a8488a94
hex13453bbf173

1324254753139 has 2 divisors, whose sum is σ = 1324254753140. Its totient is φ = 1324254753138.

The previous prime is 1324254753103. The next prime is 1324254753149. The reversal of 1324254753139 is 9313574524231.

It is a strong prime.

It is an emirp because it is prime and its reverse (9313574524231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1324254753139 - 219 = 1324254228851 is a prime.

It is a super-2 number, since 2×13242547531392 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1324254753092 and 1324254753101.

It is not a weakly prime, because it can be changed into another prime (1324254753149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662127376569 + 662127376570.

It is an arithmetic number, because the mean of its divisors is an integer number (662127376570).

Almost surely, 21324254753139 is an apocalyptic number.

1324254753139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324254753139 is an equidigital number, since it uses as much as digits as its factorization.

1324254753139 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2721600, while the sum is 49.

The spelling of 1324254753139 in words is "one trillion, three hundred twenty-four billion, two hundred fifty-four million, seven hundred fifty-three thousand, one hundred thirty-nine".