Base | Representation |
---|---|
bin | 111101101011000101… |
… | …0111100111110111101 |
3 | 110122212010101120212112 |
4 | 1323112022330332331 |
5 | 4132220201324313 |
6 | 140502040143405 |
7 | 12366020150522 |
oct | 1732612747675 |
9 | 418763346775 |
10 | 132442214333 |
11 | 511941a4990 |
12 | 21802767b65 |
13 | c648b50b80 |
14 | 65a5997149 |
15 | 36a24778a8 |
hex | 1ed62bcfbd |
132442214333 has 16 divisors (see below), whose sum is σ = 155606692416. Its totient is φ = 111133002240.
The previous prime is 132442214327. The next prime is 132442214369. The reversal of 132442214333 is 333412244231.
It is not a de Polignac number, because 132442214333 - 28 = 132442214077 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 132442214333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132442214833) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4077485 + ... + 4109837.
It is an arithmetic number, because the mean of its divisors is an integer number (9725418276).
Almost surely, 2132442214333 is an apocalyptic number.
132442214333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
132442214333 is a deficient number, since it is larger than the sum of its proper divisors (23164478083).
132442214333 is a wasteful number, since it uses less digits than its factorization.
132442214333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61004.
The product of its digits is 41472, while the sum is 32.
Adding to 132442214333 its reverse (333412244231), we get a palindrome (465854458564).
The spelling of 132442214333 in words is "one hundred thirty-two billion, four hundred forty-two million, two hundred fourteen thousand, three hundred thirty-three".
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