Cookie Consent by FreePrivacyPolicy.com
Search a number
-
+
13250244125353 = 21162797365523
BaseRepresentation
bin1100000011010001000000…
…0110000010001010101001
31201220201012021222020102111
43000310100012002022221
53214042444444002403
644103024512402321
72535204254515024
oct300642006021251
951821167866374
1013250244125353
114249440414a34
12159bb9bb463a1
137516534b0a81
1433b45b0241bb
1517ea08b2456d
hexc0d101822a9

13250244125353 has 4 divisors (see below), whose sum is σ = 13313041491088. Its totient is φ = 13187446759620.

The previous prime is 13250244125333. The next prime is 13250244125411. The reversal of 13250244125353 is 35352144205231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13250244125353 - 29 = 13250244124841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13250244125333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31398682551 + ... + 31398682972.

It is an arithmetic number, because the mean of its divisors is an integer number (3328260372772).

Almost surely, 213250244125353 is an apocalyptic number.

It is an amenable number.

13250244125353 is a deficient number, since it is larger than the sum of its proper divisors (62797365735).

13250244125353 is an equidigital number, since it uses as much as digits as its factorization.

13250244125353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62797365734.

The product of its (nonzero) digits is 432000, while the sum is 40.

The spelling of 13250244125353 in words is "thirteen trillion, two hundred fifty billion, two hundred forty-four million, one hundred twenty-five thousand, three hundred fifty-three".

Divisors: 1 211 62797365523 13250244125353