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BaseRepresentation
bin10011010010001110101…
…010001100110010000011
311200200200111011201022012
4103102032222030302003
5133203044244313433
62452450340203135
7164513523435344
oct23221652146203
94620614151265
101325243354243
1147103a362926
12194a113994ab
1397c7bb87443
14481dbd9c0cb
1524715167848
hex1348ea8cc83

1325243354243 has 2 divisors, whose sum is σ = 1325243354244. Its totient is φ = 1325243354242.

The previous prime is 1325243354221. The next prime is 1325243354333. The reversal of 1325243354243 is 3424533425231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1325243354243 - 222 = 1325239159939 is a prime.

It is a super-2 number, since 2×13252433542432 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1325243354243.

It is not a weakly prime, because it can be changed into another prime (1325243354203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662621677121 + 662621677122.

It is an arithmetic number, because the mean of its divisors is an integer number (662621677122).

Almost surely, 21325243354243 is an apocalyptic number.

1325243354243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325243354243 is an equidigital number, since it uses as much as digits as its factorization.

1325243354243 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1036800, while the sum is 41.

Adding to 1325243354243 its reverse (3424533425231), we get a palindrome (4749776779474).

The spelling of 1325243354243 in words is "one trillion, three hundred twenty-five billion, two hundred forty-three million, three hundred fifty-four thousand, two hundred forty-three".