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132654144236101 is a prime number
BaseRepresentation
bin11110001010010111110011…
…001001010010101001000101
3122101200121112101122101000221
4132022113303021102221011
5114341401141411023401
61150044250024104341
736640642233366355
oct3612276311225105
9571617471571027
10132654144236101
11392a4341153574
1212a653186050b1
135903302c99687
1424a86cdba0b65
15105098aa007a1
hex78a5f3252a45

132654144236101 has 2 divisors, whose sum is σ = 132654144236102. Its totient is φ = 132654144236100.

The previous prime is 132654144236051. The next prime is 132654144236153. The reversal of 132654144236101 is 101632441456231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123243968340900 + 9410175895201 = 11101530^2 + 3067601^2 .

It is a cyclic number.

It is not a de Polignac number, because 132654144236101 - 231 = 132651996752453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132654144236171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072118050 + 66327072118051.

It is an arithmetic number, because the mean of its divisors is an integer number (66327072118051).

Almost surely, 2132654144236101 is an apocalyptic number.

It is an amenable number.

132654144236101 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654144236101 is an equidigital number, since it uses as much as digits as its factorization.

132654144236101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 43.

The spelling of 132654144236101 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, two hundred thirty-six thousand, one hundred one".