Base | Representation |
---|---|
bin | 11110001010010111110011… |
… | …001001010010110000010011 |
3 | 122101200121112101122101200001 |
4 | 132022113303021102300103 |
5 | 114341401141411032223 |
6 | 1150044250024110431 |
7 | 36640642233400615 |
oct | 3612276311226023 |
9 | 571617471571601 |
10 | 132654144236563 |
11 | 392a4341153954 |
12 | 12a65318605417 |
13 | 5903302c99951 |
14 | 24a86cdba0db5 |
15 | 105098aa009ad |
hex | 78a5f3252c13 |
132654144236563 has 2 divisors, whose sum is σ = 132654144236564. Its totient is φ = 132654144236562.
The previous prime is 132654144236461. The next prime is 132654144236597. The reversal of 132654144236563 is 365632441456231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132654144236563 - 29 = 132654144236051 is a prime.
It is not a weakly prime, because it can be changed into another prime (132654144236363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072118281 + 66327072118282.
It is an arithmetic number, because the mean of its divisors is an integer number (66327072118282).
Almost surely, 2132654144236563 is an apocalyptic number.
132654144236563 is a deficient number, since it is larger than the sum of its proper divisors (1).
132654144236563 is an equidigital number, since it uses as much as digits as its factorization.
132654144236563 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 37324800, while the sum is 55.
The spelling of 132654144236563 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, two hundred thirty-six thousand, five hundred sixty-three".
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