Base | Representation |
---|---|
bin | 1100000110001010110100… |
… | …0011011100100000110011 |
3 | 1202002110221101012101110022 |
4 | 3001202231003130200303 |
5 | 3220402122230010003 |
6 | 44141554114554055 |
7 | 2541621265423631 |
oct | 301425503344063 |
9 | 52073841171408 |
10 | 13300122110003 |
11 | 426860621a053 |
12 | 15a979bb9892b |
13 | 756271b9c461 |
14 | 33da2d472351 |
15 | 180e77916738 |
hex | c18ad0dc833 |
13300122110003 has 4 divisors (see below), whose sum is σ = 13324436776200. Its totient is φ = 13275807443808.
The previous prime is 13300122109969. The next prime is 13300122110021. The reversal of 13300122110003 is 30001122100331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300122110003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13300122110603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12157332278 + ... + 12157333371.
It is an arithmetic number, because the mean of its divisors is an integer number (3331109194050).
Almost surely, 213300122110003 is an apocalyptic number.
13300122110003 is a deficient number, since it is larger than the sum of its proper divisors (24314666197).
13300122110003 is an equidigital number, since it uses as much as digits as its factorization.
13300122110003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24314666196.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13300122110003 its reverse (30001122100331), we get a palindrome (43301244210334).
The spelling of 13300122110003 in words is "thirteen trillion, three hundred billion, one hundred twenty-two million, one hundred ten thousand, three".
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