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133121426050564 = 2277166962487953
BaseRepresentation
bin11110010001001010111111…
…010011111100111000000100
3122110100021200001211001022221
4132101022333103330320010
5114422030140032104224
61151043045555102124
740016464015313020
oct3621127723747004
9573307601731287
10133121426050564
113946453059aa06
1212b1b9a82a1944
1359383b186c343
1424c317b971380
15105cbd90816e4
hex7912bf4fce04

133121426050564 has 24 divisors (see below), whose sum is σ = 269992751430528. Its totient is φ = 56248489879680.

The previous prime is 133121426050553. The next prime is 133121426050597. The reversal of 133121426050564 is 465050624121331.

It is a self number, because there is not a number n which added to its sum of digits gives 133121426050564.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33481241989 + ... + 33481245964.

It is an arithmetic number, because the mean of its divisors is an integer number (11249697976272).

Almost surely, 2133121426050564 is an apocalyptic number.

133121426050564 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

133121426050564 is an abundant number, since it is smaller than the sum of its proper divisors (136871325379964).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133121426050564 is a wasteful number, since it uses less digits than its factorization.

133121426050564 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66962488035 (or 66962488033 counting only the distinct ones).

The product of its (nonzero) digits is 518400, while the sum is 43.

The spelling of 133121426050564 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred twenty-six million, fifty thousand, five hundred sixty-four".