Base | Representation |
---|---|
bin | 11000110101000100… |
… | …11000001100111110 |
3 | 1021101222222100001222 |
4 | 30122202120030332 |
5 | 204300002342114 |
6 | 10042422433342 |
7 | 651222110042 |
oct | 143242301476 |
9 | 37358870058 |
10 | 13330121534 |
11 | 5720562674 |
12 | 2700292852 |
13 | 13458b7ba2 |
14 | 906540022 |
15 | 53041098e |
hex | 31a89833e |
13330121534 has 4 divisors (see below), whose sum is σ = 19995182304. Its totient is φ = 6665060766.
The previous prime is 13330121533. The next prime is 13330121573. The reversal of 13330121534 is 43512103331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43512103331 = 1039 ⋅41878829.
It is a super-2 number, since 2×133301215342 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330121533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3332530382 + ... + 3332530385.
It is an arithmetic number, because the mean of its divisors is an integer number (4998795576).
Almost surely, 213330121534 is an apocalyptic number.
13330121534 is a deficient number, since it is larger than the sum of its proper divisors (6665060770).
13330121534 is an equidigital number, since it uses as much as digits as its factorization.
13330121534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6665060769.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 13330121534 its reverse (43512103331), we get a palindrome (56842224865).
The spelling of 13330121534 in words is "thirteen billion, three hundred thirty million, one hundred twenty-one thousand, five hundred thirty-four".
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