Base | Representation |
---|---|
bin | 10011011010011010100… |
… | …100011101110000001101 |
3 | 11201112101001122200021122 |
4 | 103122122210131300031 |
5 | 133324044434041302 |
6 | 2500502451210325 |
7 | 165244404233441 |
oct | 23323244356015 |
9 | 4645331580248 |
10 | 1334033112077 |
11 | 47483aa05aa6 |
12 | 196664ba69a5 |
13 | 98a4cc05593 |
14 | 487d34c6821 |
15 | 24a7bb653a2 |
hex | 1369a91dc0d |
1334033112077 has 2 divisors, whose sum is σ = 1334033112078. Its totient is φ = 1334033112076.
The previous prime is 1334033111989. The next prime is 1334033112103. The reversal of 1334033112077 is 7702113304331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 881657149156 + 452375962921 = 938966^2 + 672589^2 .
It is a cyclic number.
It is not a de Polignac number, because 1334033112077 - 214 = 1334033095693 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334033114077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667016556038 + 667016556039.
It is an arithmetic number, because the mean of its divisors is an integer number (667016556039).
Almost surely, 21334033112077 is an apocalyptic number.
It is an amenable number.
1334033112077 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334033112077 is an equidigital number, since it uses as much as digits as its factorization.
1334033112077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31752, while the sum is 35.
The spelling of 1334033112077 in words is "one trillion, three hundred thirty-four billion, thirty-three million, one hundred twelve thousand, seventy-seven".
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