Base | Representation |
---|---|
bin | 10011011010101100010… |
… | …101101111011111001001 |
3 | 11201120010211122021020222 |
4 | 103122230111233133021 |
5 | 133330202244224231 |
6 | 2500552221155425 |
7 | 165254654265251 |
oct | 23325425573711 |
9 | 4646124567228 |
10 | 1334331242441 |
11 | 47498322282a |
12 | 1967289bbb75 |
13 | 98a998ca392 |
14 | 48820d30961 |
15 | 24a97e0527b |
hex | 136ac56f7c9 |
1334331242441 has 2 divisors, whose sum is σ = 1334331242442. Its totient is φ = 1334331242440.
The previous prime is 1334331242417. The next prime is 1334331242473. The reversal of 1334331242441 is 1442421334331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1292143725625 + 42187516816 = 1136725^2 + 205396^2 .
It is an emirp because it is prime and its reverse (1442421334331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1334331242441 - 234 = 1317151373257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1334331242141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667165621220 + 667165621221.
It is an arithmetic number, because the mean of its divisors is an integer number (667165621221).
Almost surely, 21334331242441 is an apocalyptic number.
It is an amenable number.
1334331242441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334331242441 is an equidigital number, since it uses as much as digits as its factorization.
1334331242441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 82944, while the sum is 35.
Adding to 1334331242441 its reverse (1442421334331), we get a palindrome (2776752576772).
The spelling of 1334331242441 in words is "one trillion, three hundred thirty-four billion, three hundred thirty-one million, two hundred forty-two thousand, four hundred forty-one".
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