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BaseRepresentation
bin1100001010110100110000…
…1011010010111100101011
31202101010101020212220212012
43002231030023102330223
53223204421344003101
644242422243310135
72550452244206015
oct302551413227453
952333336786765
1013380101156651
114299518314609
1216011a097b34b
13760979878c28
143438595151b5
151830a9146bbb
hexc2b4c2d2f2b

13380101156651 has 4 divisors (see below), whose sum is σ = 13664784160032. Its totient is φ = 13095418153272.

The previous prime is 13380101156641. The next prime is 13380101156677. The reversal of 13380101156651 is 15665110108331.

13380101156651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13380101156651 - 214 = 13380101140267 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13380101156599 and 13380101156608.

It is not an unprimeable number, because it can be changed into a prime (13380101156641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142341501620 + ... + 142341501713.

It is an arithmetic number, because the mean of its divisors is an integer number (3416196040008).

Almost surely, 213380101156651 is an apocalyptic number.

13380101156651 is a deficient number, since it is larger than the sum of its proper divisors (284683003381).

13380101156651 is an equidigital number, since it uses as much as digits as its factorization.

13380101156651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 284683003380.

The product of its (nonzero) digits is 64800, while the sum is 41.

The spelling of 13380101156651 in words is "thirteen trillion, three hundred eighty billion, one hundred one million, one hundred fifty-six thousand, six hundred fifty-one".

Divisors: 1 47 284683003333 13380101156651