Base | Representation |
---|---|
bin | 11110011101011000101000… |
… | …110001100111000101000111 |
3 | 122120022112000111021020220021 |
4 | 132131120220301213011013 |
5 | 120024303020244243012 |
6 | 1152524411421520011 |
7 | 40134225242536666 |
oct | 3635305061470507 |
9 | 576275014236807 |
10 | 133960714056007 |
11 | 39758468810693 |
12 | 13036598113007 |
13 | 599959721c4c7 |
14 | 2511a39ac6ddd |
15 | 107495b5b9007 |
hex | 79d628c67147 |
133960714056007 has 2 divisors, whose sum is σ = 133960714056008. Its totient is φ = 133960714056006.
The previous prime is 133960714055957. The next prime is 133960714056041. The reversal of 133960714056007 is 700650417069331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133960714056007 - 243 = 125164621033799 is a prime.
It is a super-2 number, since 2×1339607140560072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133960714056097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66980357028003 + 66980357028004.
It is an arithmetic number, because the mean of its divisors is an integer number (66980357028004).
Almost surely, 2133960714056007 is an apocalyptic number.
133960714056007 is a deficient number, since it is larger than the sum of its proper divisors (1).
133960714056007 is an equidigital number, since it uses as much as digits as its factorization.
133960714056007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2857680, while the sum is 52.
The spelling of 133960714056007 in words is "one hundred thirty-three trillion, nine hundred sixty billion, seven hundred fourteen million, fifty-six thousand, seven".
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