1340402030341 has 4 divisors (see below), whose sum is σ = 1462256760384. Its totient is φ = 1218547300300.

The previous prime is 1340402030333. The next prime is 1340402030413. The reversal of 1340402030341 is 1430302040431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1340402030341 - 2³ = 1340402030333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340402030311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60927365005 + ... + 60927365026.

It is an arithmetic number, because the mean of its divisors is an integer number (365564190096).

Almost surely, 2^{1340402030341} is an apocalyptic number.

1340402030341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1340402030341 is a deficient number, since it is larger than the sum of its proper divisors (121854730043).

1340402030341 is a wasteful number, since it uses less digits than its factorization.

1340402030341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121854730042.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1340402030341 its reverse (1430302040431), we get a palindrome (2770704070772).

The spelling of 1340402030341 in words is "one trillion, three hundred forty billion, four hundred two million, thirty thousand, three hundred forty-one".