1340440133 has 4 divisors (see below), whose sum is σ = 1345015308. Its totient is φ = 1335864960.

The previous prime is 1340440121. The next prime is 1340440151. The reversal of 1340440133 is 3310440431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1026689764 + 313750369 = 32042^2 + 17713^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340440133 - 2²² = 1336245829 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340440099 and 1340440108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340440103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2287148 + ... + 2287733.

It is an arithmetic number, because the mean of its divisors is an integer number (336253827).

Almost surely, 2^1340440133 is an apocalyptic number.

It is an amenable number.

1340440133 is a deficient number, since it is larger than the sum of its proper divisors (4575175).

1340440133 is an equidigital number, since it uses as much as digits as its factorization.

1340440133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4575174.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1340440133 is about 36612.0217005289. The cubic root of 1340440133 is about 1102.5944634825.

Adding to 1340440133 its reverse (3310440431), we get a palindrome (4650880564).

The spelling of 1340440133 in words is "one billion, three hundred forty million, four hundred forty thousand, one hundred thirty-three".